Publisher's Synopsis
This is the answer key of Volume 7 of the entire set of 12 volumes of word problems solving strategies. If you want to set a solid foundation in math, grasping the techniques on solving word problems is the key to it. This set of books teaches you the techniques and strategies you need to solve word problems. Sample question in this volume: Miss Lee's class has 25 students and each student has read 4 books during the month. If the number of books all the students in Miss Lee's class read is twice the number of books all the students in Mr. Smith's class have read, how many books have the students in Mr. Smith's class read altogether? Reasoning and solution: Let's first find how many books all the students in Miss Lee's class have read: Each student reads 4 books so 25 students read 25 groups of 4 books. Since each student reads the same number of books we can use the 3 elements formulas to solve the problem: We use multiplication to find the total number of books that all the students in Miss Lee's class read: 4 x 25=100 books Twice = 2 groups of so we can use the 3 elements formulas to solve the problem: 100 books are twice or 2 groups of the number of books that all the students in Mr. Smith's class have read or 100 books are 2 groups of the number of books that all the students in Mr. Smith's class read. We divide the number of groups, 2, into the total number of books, 100, to find the amount in each group or the number of books that all the students in Mr. Smith's class have read: 100
